How many 2×1 MUXes are needed for 8×1 mux?

How many 2×1 MUXes are needed for 8×1 mux?

So, we require two 8×1 Multiplexers in first stage in order to get the 16 data inputs. Since, each 8×1 Multiplexer produces one output, we require a 2×1 Multiplexer in second stage by considering the outputs of first stage as inputs and to produce the final output.

How many 4×1 multiplexers are required to construct a 16×1 multiplexer?

At first stage: 4 multiplexers are needed for 16 inputs, At second stage: the output of these 4 multiplexers is connected to inputs of 1 multiplexer. Total 4 × 1 multiplexers needed are 4 + 1 = 5.

How do you implement 8×1 mux using 4×1 mux?

The higher order marks by using the lower order MUX. So let’s use this table before that I will make 2 4 cross 1 MUX. That. We will use for the implementation.

How do you create a 16 1 multiplexer?

The basis: See it this way: You need a combinational logic with 16 input pins, 4 select lines and one output. In a 4:1 mux, you have 4 input pins, two select lines and one output. So, at the least you have to use 4 4:1 MUX, to obtain 16 input lines. But you’d then have a logic with 4 output pins.

How many data selection lines are required for design 16×1 multiplexer?

So the number of select lines will be 4.

How many 4 input MUXS are needed to implement a 256 input MUX and the number of levels that are required?

The number of 4 input mux that are needed to implement 256 input mux is 85. As we know 256 input mux will contain 256 lines of input.

How many 4 input MUXS are needed to implement a 256 input mux and the number of levels that are required?

What is the minimum number of 4×1 multiplexers required to implement a full adder?

Full Adder using 4 to 1 Multiplexer:

A 4 to 1 line multiplexer has 4 inputs and 1 output line.In our experiment,we use IC 74153(Multiplexer) and IC 7404(NOT gate) for implementing the full adder.

What is 8×1 multiplexer?

An 8-to-1 multiplexer consists of eight data inputs D0 through D7, three input select lines S0 through S2 and a single output line Y. Depending on the select lines combinations, multiplexer selects the inputs.

Which of the following are used to implement 8×1 mux?

Circuit Diagram
Two 4:1 muxes, an OR gate, and a NOT gate as an enable signal can be used to create an 8:1 multiplexer.

How many select lines will a 16 to 1 multiplexer have?

4
So the number of select lines will be 4.

What is multiplexer design and explain about 16 1 multiplexer?

In the 16 to 1 multiplexer, there are total of 16 inputs, i.e., A0, A1, …, A16, 4 selection lines, i.e., S0, S1, S2, and S3 and single output, i.e., Y. On the basis of the combination of inputs that are present at the selection lines S0, S1, and S2, one of these 16 inputs will be connected to the output.

Can we design a 4×1 mux with two 2×1 multiplexers?

Yes, it can, as in post #2. Otherwise one channel on each will always be on. True (without a disable pin), but there is nothing in post #1 about this being a not allowed condition. I am assuming these are analog multiplexers (passing an analog signal) so a digital logic front end cannot be used.

How many lines will a 64 to 1 multiplexer have?

Using the above formula, we can obtain the same. Hence, total number of 4 : 1 MUX are required to implement 64 : 1 MUX = 16 + 4 + 1 = 21.

What is the minimum number of 2 1 MUX are required to implement two input AND gate?

We need to implement 4 to 1 Mux using 2 to 1 Mux. We need 4/2 = 2 in first level and 2/2 = 1 in second level. Hence, we need three 2 to 1Multiplexers to implement 4 to 1 Mux.

How many 2 1 MUXS are required to realize the 32 1 mux?

To implement 2n × 1 MUX using 2 × 1 MUX, the total number of 2 × 1 MUX required is (2n – 1). The sum will give the total number of MUX required to implement 16 × 1 multiplexer using 2 × 1, i.e.
…
4.6.

How many 2×1 mux are required for implementing the half adder?

The carry can be implemented by using only one 2 × 1 MUX as shown below. Therefore, we require minimum three multiplexers to implement a half adder.

How many 4 input mux are needed to implement 256 input mux and number of levels that are required?

How many 2 1 mux is required to implement the NOT operation?

two 2:1 Mux
Implementation of NAND, NOR, XOR and XNOR gates requires two 2:1 Mux.

How many 2 1 MUX is required to implement the and operation?

Implementation of NAND, NOR, XOR and XNOR gates requires two 2:1 Mux. First multiplexer will act as NOT gate which will provide complemented input to the second multiplexer.

How many 2 1 MUX is required to implement the or operation?

c) Implementation of OR gate using 2 : 1 Mux using “n-1” selection lines. Implementation of NAND, NOR, XOR and XNOR gates requires two 2:1 Mux.

How many select lines does a 17 to 1 multiplexer have?

What are the minimum number of 2 to 1 multiplexers required?

We need 4/2 = 2 in first level and 2/2 = 1 in second level. Hence, we need three 2 to 1Multiplexers to implement 4 to 1 Mux.

How do I get a higher order multiplexer?

It is also common to combine to lower order multiplexers like 2:1 and 4:1 MUX to form higher order MUX like 8:1 Multiplexer. Now, for example let us try to implement a 4:1 Multiplexer using a 2:1 Multiplexer. To construct a 4:1 MUX using a 2:1 MUX, we will have to combine three 2:1 MUX together.

What is select line in a 64 to 1 multiplexer?

A: The select lines are present in a 64:1 mux are: 2×2×2×2×2×2=64 2n input lines, n selection lines…